A bath tub full of lukewarm water hold more heat than a teakettle full of boiling water? True or False?

I would figure it out this way;


Say a bath tub is 22x52x9 = 10296 cubic inches or 169 liters.


Say my teakettle holds just one liter.


Boiling teakettle 100 deg C times 1000 ml = 100,000 calories


Lukewarm bath tub at say 32 deg C (=90F) is:


32 times 169,000 ml = 5,408,000 latent heat calories.


Answer: TRUE


NOTE; you have to be a little more picky with units to be exactly correct, but the logic is the same. Just note that Specific heat is really measured in cal/g. 1 cal/gr = 4.184 J/kg = 1.80 Btu/lbA bath tub full of lukewarm water hold more heat than a teakettle full of boiling water? True or False?
True, I agree with coffeebr....A bath tub full of lukewarm water hold more heat than a teakettle full of boiling water? True or False?
i think it is true
True. Unless the teakettle is really really big and the tub is really small.
false
Let, mass of the tub water is m1.dT1 is the change in temperature due to boiling of the water from a reference temperature. Cp is the specific heat of the water, then for the first case, Q1=m1*cp*dT1


similarly, if mass of the kettle water is m2. dT2 is the change in temperature due to boiling of the water from a reference temperature, then Q2=m2*Cp*dT2. So, above question will be true if m1*dT1%26gt;m2*dT2, other wise false.